How do you solve the system of equations 3x + 2y = 43x+2y=4 and 4x + 3y = 74x+3y=7?

1 Answer
iceman
Mar 18, 2017

(-2, 5)(−2,5)

Explanation:

3x+2y=43x+2y=4
4x+3y=74x+3y=7
Multiply the 1st and 2nd equations by 3 and -2 respectively:
9x+6y=129x+6y=12
-8x-6y=-14−8x−6y=−14 => add the equations y's cancel, solve for x:
x=-2x=−2 => plug in the 1st equation solve for y:
-6+2y=4−6+2y=4
2y=102y=10
y=5y=5
Hence the solution set is:
(x, y)=(-2, 5)(x,y)=(−2,5)

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