How do you solve the system of equations #3x + 5y - 30 = 0# and #x - y - 2 = 0#?

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Answer 1 · 2015-09-23T11:50:59

#x = 5#
#y=3#

#3x+5y−30=0#---------------(1)
#x−y−2=0# -------------------(2)

Solve the equation (2) for #y#

#-y = 2-x#
#y = -2+x#

Substitute the value of #y = -2+x# in equation (1)
#3x+5( -2+x)−30=0#

Simplify

#3x -10+5x −30=0#
#8x −40=0#
#8x =40#
#x=40/8=5#
#x = 5#

Substitute #x = 5# in equation (2)

#5−y−2=0#

Simplify -
#3-y=0#
#-y =-3#
#y=3#