How do you solve the system of equations $8 x + 3 y = 93$ $8x + 3y = 93$ and $4 x + 3 y = 69$ $4x + 3y = 69$ ?

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Answer 1 · 2018-04-30T01:05:54

$y = 15$ $y=15$
$x = 6$ $x=6$

$8 x + 3 y = 93$ $8x+3y=93$ --- (1)
$4 x + 3 y = 69$ $4x+3y=69$ --- (2)

(1) minus (2)
$4 x = 24$ $4x=24$
$x = 6$ $x=6$ --- (3)

Sub (3) into (2)
$4 (6) + 3 y = 69$ $4(6)+3y=69$
$24 + 3 y = 69$ $24+3y=69$
$3 y = 45$ $3y=45$
$y = 15$ $y=15$

How do you solve the system of equations 8x+3y=938x + 3y = 93 and 4x+3y=694x + 3y = 69?