How do you solve the system of equations $a + 3 b = 13$ $a + 3b = 13$ and $a + b = 5$ $a + b = 5$ ?

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Answer 1 · 2017-10-17T07:36:03

$a = 1, b = 4$ $a=1,b=4$

another way is by elimination

$a + 3 b = 13 - - (1)$ $a+3b=13--(1)$

$a + b = 5 - - (2)$ $a+b=5--(2)$

subtract $(2) - (1)$ $(2)-(1)$

$2 b = 8 \Rightarrow b = 4$ $2b=8=>b=4$

substituting into #(2)

$a + 4 = 4 \Rightarrow a = 1$ $a+4=4=>a=1$

$a = 1, b = 4$ $a=1,b=4$

check for consistency in $(1)$ $(1)$

$1 + 3 \times 4 = 1 + 12 = 13 \sqrt{}$ $1+3xx4=1+12=13sqrt$

How do you solve the system of equations a+3b=13a + 3b = 13 and a+b=5a + b = 5?