How do you solve the system of equations algebraically $\frac{3}{5} x - \frac{1}{6} y = 1, \frac{1}{5} x + \frac{5}{6} y = 11$ $3/5x-1/6y=1, 1/5x+5/6y=11$ ?

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How do you solve the system of equations algebraically $\frac{3}{5} x - \frac{1}{6} y = 1, \frac{1}{5} x + \frac{5}{6} y = 11$ $3/5x-1/6y=1, 1/5x+5/6y=11$ ?

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Answer 1 · 2017-08-12T16:04:59

$y = 12, x = 5$ $y=12,x=5$

Explanation:

$\frac{3}{5} x - \frac{1}{6} y = 1$ $3/5 x-1/6 y=1$ ------(1)

$\frac{1}{5} x + \frac{5}{6} y = 11$ $1/5 x+5/6 y=11$ ------(2)

$:.(1) xx 5$

$:.(5)3/5x-(5)1/6y=5$

$:.15/5x-5/6y=5$

$:.3x-5/6 y=5$ ------(3)

$:.(2)+(3)$

$:.3 1/5x=16$

$:.16/5 x=16$

$:.x=16/(16/5)$

$:.x=cancel(16)^1/1 xx 5/cancel(16)^1$

$:.color(magenta)(x=5$

substitute $color(magenta)(x=5$ in(1)

$:.3/5(color(magenta)5)-1/6 y=1$

$:.15/5-1/6y=1$

$:.3-1/6 y=1$

$:.-1/6 y=1-3$

$:.-1/6 y=-2$

$:.y=2/(1/6)$

$:.y=2 xx 6$

$:.color(magenta)(y=12$

substitute $color(magenta)(y=12,x=5$ in (2)

$:.1/5(color(magenta)5)+5/6(color(magenta)12)=11$

$:.5/5+60/6=11$

$:.1+10=11$

$:.color(magenta)(11=11$

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How do you solve the system of equations algebraically $\frac{3}{5} x - \frac{1}{6} y = 1, \frac{1}{5} x + \frac{5}{6} y = 11$ $3/5x-1/6y=1, 1/5x+5/6y=11$ ?

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How do you solve the system of equations algebraically $\frac{3}{5} x - \frac{1}{6} y = 1, \frac{1}{5} x + \frac{5}{6} y = 11$ $3/5x-1/6y=1, 1/5x+5/6y=11$ ?