How do you solve the system of equations algebraically #3x-5y+z=9, x-3y-2z=-8, 5x-6y+3z=15#?
1 Answer
Jul 8, 2017
Explanation:
#"using the process of elimination"#
#color(blue)" eliminating z"#
#3x-5y+z=9to(1)#
#x-3y-2z=-8to(2)#
#5x-6y+3z=15to(3)#
#(2)+2xx(1)larr" row operation"#
#7x-13y=10to(4)#
#(3)-3xx(1)larr" row operation"#
#-4x+9y=-12to(5)#
#color(blue)" eliminating x"#
#4xx(4)+7xx(5)larr" row operation"#
#11y=-44tocolor(red)(y=-4)#
#"substituting in " (4)#
#7x+52=10tocolor(red)(x=-6)#
#"substituting in " (1)#
#-18+20+z=9tocolor(red)(z=7)#
#color(blue)"As a check"" in " (2)#
#-6+12-14=-8rarr" True"#
#rArr(-6,-4,7)" is the solution"#