How do you solve the system of equations #y=x+3# and #y=3x+5#?

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Answer 1 · 2016-11-23T14:02:08

#x = -1# and #y = 2#

Because we are given #y = x + 3# we can substitute #x + 3# for #y# in the second equation and solve for #x#:

#x + 3 = 3x + 5#

#x + 3 - x - 5 = 3x + 5 - x - 5#

#-2 = 2x#

#(-2)/2 = (2x)/2#

#x = -1#

We can now substitute #-1# for #x# in the first equation to find #y#:

#y = -1 + 3#

#y = 2#