How do you solve the system of linear equations #-3x + 2y = 8# and #7x - 4y = 16#?

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Answer 1 · 2017-02-04T06:57:59

#x=32, y=52.#

Multiplying the #1^(st)" eqn. by "2" gives, "-6x+4y=16#,

and, adding this to the #2^(nd)# eqn., we get,

#-6x+cancel(4y)+7xcancel(-4y)=16+16, i.e., x=32.#

Then, using this in the #1^(st)# eqn., we get,

#-3(32)+2y=8 rArr-96+2y=8 rArr 2y=8+96=104#

#:. y=104/2=52.#

Hence, the Soln. #x=32, y=52.#