How do you solve the system using the elimination method for 3x – 2y – 7 = 0 and 5x + y - 3 = 0?

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Answer 1 · 2018-07-23T02:22:51

#x=1 and y=-2#

Here ,

#3x-2y=7....to(1)#

#5x+y=3......to(2)#

Multiplying eqn. #(2)# by #2# and adding:

#i.e. (1)+2xx(2)# we get

#3x-cancel(2y)=7#
#ul(10x+cancel(2y)=6#
#13x+0=13#

#:.x=1#

Subst. #x=1# into #eqn.(2)# we get

#5(1)+y=3#

#:.5+y=3#

#:.y=3-5#

#:.y=-2#

Hence,

#x=1 and y=-2#