Question

How do you solve the system `x^2-16y^2=16` and `x^2+y^2=9`?

Answer 1

The system of equations don't have real solution.

Explanation:

Making `x_2=x^2` and `y_2=y^2`

`{(x_2 - 16 y_2 = 16), (x_2 + y_2 = 9):}`

and solving we have

`x_2 = 160/17, y_2=-7/17`

obviously the solution for `y_2` is not feasible so the system has not real solutions.