How do you solve the system #x^2-2x+4+y^2-10=0# and #2y^2-x+3=0#?
1 Answer
Aug 25, 2016
Explanation:
From the second eqn., we have,
We subst. this in the first eqn., and , get,
To solve this Quadr. Eqn., we use the Formula : The Roots,
Applying this Formula, with
Then, since, y^2=(x-3)/2, we get,
But, in
Hence,