How do you solve the system #x^2=6y# and #y=-x#? Precalculus Solving Systems of Two Equations Solving by Substitution 1 Answer S.S Oct 5, 2016 #x = -6# Explanation: As # y = -x#, #6y = -6x# So #x^2 = -6x# Therefore; #x = -6# Now we substitute #x# into an earlier equation which still has #y# in it. # y = color (blue)(-x)# # y = - color (blue)(-6)# # y = 6 # Answer link Related questions What is a system of equations? What does it mean to solve a system of equations by substitution? How do I use substitution to find the solution of the system of equations #c+3d=8# and #c=4d-6#? How do you write a system of linear equations in two variables? How does a system of linear equations have no solution? How many solutions can a system of linear equations have? What is the final step of completing a solve by substitution problem? How do I use substitution to find the solution of the system of equations #4x+3y=7# and #3x+5y=8#? How do I use substitution to find the solution of the system of equations #y=2x+1# and #2y=4x+2#? How do I use substitution to find the solution of the system of equations #y=1/3x+7/3# and... See all questions in Solving by Substitution Impact of this question 1240 views around the world You can reuse this answer Creative Commons License