How do you solve the system #x^2+y^2-4x-4y=26# and #x^2+y^2-4x=54# and #y=3x-8#?
1 Answer
Sep 8, 2016
Explanation:
Subtracting the first from the second we get
Solving
we obtain
Substituting those results in the first
Substituting now in the second
so the system has the solution