How do you solve the system : #x-3y=-2#, #4x-2y=-8 #?
1 Answer
Jun 21, 2018
Here
Explanation:
we have two equations
let
and
Now we have to subsitute or eliminate either x or y
let us eliminate y
now multiply eq(1) with 2 and eq(2) with 3,we will get
now subtract eq(1) from eq(2)
we will get
x=-2
putting y in eq(1) and eq(2)
we get y=0.