How do you solve the system $x + 5 y = 2$ $x+5y=2$ and $x - 1 = 2 y$ $x-1=2y$ ?

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Answer 1 · 2015-05-19T14:30:14

You can isolate one variable in one equation and, then, substitute its value in the other equation:

Let's isolate $x$ $x$ in the first equation, for example.

$x = 2 - 5 y$ $x=2-5y$

Now, substituting it:

$(2 - 5 y) - 1 = 2 y$ $(2-5y)-1=2y$
$1 = 7 y$ $1=7y$
$y = \frac{1}{7}$ $y=1/7$

Now, as we know $x = 2 - 5 y$ $x=2-5y$ and $y = \frac{1}{7}$ $y=1/7$ ,

$x = 2 - 5 (\frac{1}{7})$ $x=2-5(1/7)$
$x = 2 - \frac{5}{7}$ $x=2-5/7$
$x = \frac{9}{7}$ $x=9/7$

How do you solve the system x+5y=2x+5y=2x+5y=2 and x-1=2yx−1=2yx-1=2y?