How do you solve the system $x + 6 y = - 1, 5 x + 7 y = - 5$ $x+6y=-1, 5x+7y=-5$ using the substitution method?

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Answer 1 · 2016-11-21T05:06:51

$x = - 1$ $x=-1$
$y = 0$ $y=0$

$x + 6 y = - 1$ $x+6y=-1$
$x = - 6 y - 1$ $x=-6y-1$

$5 x + 7 y = - 5$ $5x+7y=-5$

$5 (- 6 y - 1) + 7 y = - 5$ $5(-6y-1)+7y=-5$
$- 30 y - 5 + 7 y = - 5$ $-30y-5+7y=-5$
$- 23 y = 0$ $-23y=0$
$y = 0$ $y=0$

$x = - 6 y - 1$ $x=-6y-1$
$x = - 6 (0) - 1$ $x=-6(0)-1$
$x = - 1$ $x=-1$

How do you solve the system x+6y=−1,5x+7y=−5x+6y=-1, 5x+7y=-5 using the substitution method?