How do you solve the system y=2x-2y=2x2 and y=x+2y=x+2 using substitution?

1 Answer
Mar 19, 2017

The solution is (4, 6).

Explanation:

Using substitution in this case means plugging in x+2x+2 for yy (for example), since they are stated to be equal.

y = 2x-2 color(white)"X" & color(white)"X" y = x+2y=2x2X&Xy=x+2

Therefore, 2x-2 = x+22x2=x+2
color(white)"XXXXXXX-X" 2x = x+4XXXXXXX-X2x=x+4
color(white)"XXXXXXXXX" x = 4XXXXXXXXXx=4

Now we know that x=4x=4, so plug in xx to one of the equations in order to find yy.

y = x+2y=x+2
y = 4+2y=4+2
y = 6y=6

So, the solution is (4, 6).