Question

How do you solve the system `y= 2x + 5` and `y= 3x - 8` by substitution?

Answer 1

You substitute the `y`-value of one equation as expressed in `x` into the other.

In this case we get:
`2x+5=3x-8`, subtract `2x` from both sides
`->5=x-8`, add `8` to both sides
`->13=x->x=13`