How do you solve the system #y=2x# and #x+3y=-14# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Serena D. Apr 21, 2018 #(-2, -4)# Explanation: Substitute the #2x# in for #y# in the second equation: #x+3(2x)=-14# #x+6x=-14# #7x=-14# #x=-2# We know that #x# is #-2# and that #y# is #2*x#. #y=2*-2# #y=-4# #(-2, -4)# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 5487 views around the world You can reuse this answer Creative Commons License