How do you solve the system #y=6x# and #2x+3y=-20# using substitution?

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Answer 1 · 2018-04-25T00:53:43

#2x + 3(6x) = -20 # means # x = -1# and #y = 6x = -6#.

We can just plug #y=6x# into #2x + 3y=-20# and get

#2x + 3(6x) = -20 #

#20 x = -20#

# x = -1#

# y = 6x = -6 #

Check:

# -6 = 6 (-1) quad sqrt #

#2 (-1) + 3(-6) = -20 quad sqrt #