How do you solve the system #y=x+2# and #y+1=2x# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer George C. May 24, 2015 Use the formula for #y# given to us in the first equation, substituting it into the second equation: #2x = y + 1 = (x+2) + 1 = x+3# Subtract #x# from both sides to get: #x=3# Substitute #x=3# in the first equation to get: #y = x+2 = 3+2 = 5# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1304 views around the world You can reuse this answer Creative Commons License