How do you solve the system $y = - x + 2$ $y=-x+2$ and $y = x - 4$ $y=x-4$ ?

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Answer 1 · 2016-06-12T20:08:13

$x = 3, y = - 1$ $x= 3, y = -1$

These equations are both in the form $y = .........$
Because y = y, it follows that the right sides of the equations are also equal.

$" " y = y$
$" "x - 4 = -x +2$

$2x = 2+4$
$2x = 6$
$x = 3$

Now substitute x = 3 into both equations given toi make sure the answer for $y$ is the same.

$y = 3 -4 = -1" and "y = -(3) + 2 = -1$

$y = -1$

How do you solve the system y=-x+2y=−x+2y=-x+2 and y=x-4y=x−4y=x-4?