Question

How do you solve the system `y = x +4` and `2x + 3y = 22` by substitution?

Answer 1

You are given `y=color(red)(x+4)`, so substitute this for the value of `y` in
`2x+3y = 22`

`2x + 3color(red)((x+4)) = 22`

`2x+3x+12 =22`

`5x= 10`

`x=color(blue)(2)`

Now substitute this value for `x` back into `y=x+4`
`y=color(blue)(2)+4`

`y=6`