How do you solve the triangle given $A=60$ degrees, $a=20((3)^(1/2)), b=40?$

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Answer 1 · 2016-02-29T15:56:38

B = 90 deg. So, C= 180 $-$ ( 60 + 90 ) = 30 deg..

sin B = b/a sin A gives B. C = 180 $-$ ( A + B )
a, b and included angle C are known. So, the triangle is fixed.

How do you solve the triangle given A=60A=60 degrees, a=20((3)^(1/2)), b=40?a=20((3)^(1/2)), b=40?