Question

How do you solve the triangle given C=85°20', a=35, c=50?

Answer 1

Use the trig identity: sin A/a = sin C/c
sin A = sin C.(a/c) = 0,99 (35/50) = 0. 69--> A = 43.87 deg
B = 180 - 85.20 - 43.87 = 50.93