How do you solve the triangle given #triangleABC, a=15, b=19, mangleC=60#?

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Answer 1 · 2017-11-01T16:21:12

#c~~17.34, A=48^@29', B=71^@31'#

Use the Law of Cosine

#c^2=a^2+b^2-2ab cos C#

#c=sqrt(15^2+19^2-2(15)(19)cos60^@#

#c~~17.34#

#sin A/15 =sin60^@/17.34935157#

#sin A =(15 sin60^@)/17.34935157#

#A=sin^-1((15 sin60^@)/17.34935157)=48^@29'#

#B=180^@-60^@-48^@29'=71^@31'#