How do you solve this logarithmic equation?

Question

#3ln x-7=4#

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Answer 1 · 2016-11-21T21:39:41

39.1213

#3lnx-7=4#
#3lnx=11#
#lnx=11/3#
Or
#log_e x=11/3#
Remember #2^3=8# is the same fact as#log_2 8=3#
So
#e^(11/3)=x#
X=39.1213 to 4dp