How do you solve this question? When #1<=x<=8# and #log_2(y)=[log_2(x)]^2# is given, What is maximum and minimum value of #x^2/y#?
2 Answers
Jan 16, 2018
Maximum value = 2
Explanation:
When we put
We get,
We get y = 2
Put the values of x and y in the equation
=
= 2
This is the maximum value
I am not sure for the minimum
It should be
Hope it helps you
Jan 16, 2018
See below.
Explanation:
From
making
and we have the pairs
So, for integer values in the feasible region, we have