How do you solve this system of equations $2 x - 4 y = - 24, 3 x + 4 y = 4$ $2x - 4y = - 24 , 3x + 4y = 4$ ?

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Answer 1 · 2018-05-03T09:39:35

Add these two to find x first. Your solution: $x = - 4$ $x=-4$ and $y = 4$ $y=4$

$2 x - 4 y = - 24$ $2x - 4y = -24$

$3 x + 4 y = 4$ $3x + 4y = 4$

After summing them up:

$2 x + 3 x - 4 y + 4 y = - 24 + 4$ $2x + 3x - 4y + 4y = -24 + 4$

$5 x = - 20$ $5x = -20$

$x = - \frac{20}{5} = - 4$ $x = -20/5 = -4$

Now y can be computed:

$4 y = 4 - 3 x$ $4y = 4 - 3x$

$4 y = 4 - (3 \times - 4)$ $4y = 4 -(3times-4)$

$4 y = 4 + 12$ $4y = 4 + 12$

$y = \frac{16}{4} = 4$ $y = 16/4 = 4$

How do you solve this system of equations 2x - 4y = - 24 , 3x + 4y = 42x−4y=−24,3x+4y=42x - 4y = - 24 , 3x + 4y = 4?