How do you solve using the square root property ${(x + 8)}^{2} = 81$ $(x + 8)^2 = 81$ ?

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Answer 1 · 2018-03-30T01:16:08

$x = 1$ $x= 1$ or $x = - 17$ $x = -17$ .

Take the square root of both sides.

$\sqrt{{(x + 8)}^{2}} = \pm \sqrt{81}$ $sqrt((x+ 8)^2) = +-sqrt(81)$

$x + 8 = \pm 9$ $x + 8 = +-9$

$x = 1 or - 17$ $x = 1 or -17$

Hopefully this helps!

How do you solve using the square root property (x+8)2=81(x + 8)^2 = 81?