How do you solve #v^2+7v+12=0#?

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Answer 1 · 2016-11-11T13:14:47

#v = -4# and #v = -3#

#v^2 + 7v + 12 = 0#

#(v + 4)(v + 3) = 0#

Then solve for each term of the quadratic:

1)

#((v + 4)(v + 3))/(v + 3) = 0/(v + 3)#

#v + 4 = 0#

#v + 4 - 4 = 0 - 4#

#v = -4#

2)

#((v + 4)(v + 3))/(v + 4) = 0/(v + 4)#

#v + 3 = 0#

#v + 3 - 3 = 0 - 3#

#v = -3#