How do you solve #w/6> -3#?
1 Answer
Nov 24, 2017
Explanation:
#"multiply through by 6"#
#cancel(6)xxw/cancel(6)> (6xx-3)#
#rArrw> -18#
#"multiply through by 6"#
#cancel(6)xxw/cancel(6)> (6xx-3)#
#rArrw> -18#