How do you solve #(x+1)/3 = (x-1)/4#?

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Answer 1 · 2016-06-05T06:12:06

x=-7

4(x+1)=3(x-1)
4x+4=3x-3
4x-3x=-4-3
x=-7

Answer 2 · 2016-06-05T06:14:59

#x=-7#

In the equation #(x+1)/3=(x-1)/4#, let us first multiply both sides by LCD of #3# and #4# i.e. #12# to eliminate fractions.

Hence this equation can be written as

#(x+1)/3xx12=(x-1)/4xx12#

#4(x+1)=3(x-1)# or

#4x+4=3x-3#

now transposing terms containing variable #x# to left hand side and constant terms to right hand side, we get

#4x-3x=-3-4# or

#x=-7#