How do you solve #x^2 + 16x + 64 = 81#?

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Answer 1 · 2018-03-21T16:08:55

#x=1, -17#

rearrange to the form

#ax^2+bx+c=0#

then factorise

#x^2+16x+64=81#

#x^2+16x-17=0#

#(x+17)(x-1)=0#

#" either "x+17=0=>x=-17#

#" or "x-1=0=>x=1#

#:.x=1,-17#