How do you solve $x^{2} + 25 < 10 x$ $x^2+25<10x$ using a sign chart?

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Answer 1 · 2016-12-14T07:33:31

The answer is $S = {\emptyset}$ $S={O/ }$

Let's rewrite the equation as

$x^{2} - 10 x + 25 < 0$ $x^2-10x+25<0$

Let's factorise,

${(x - 5)}^{2} < 0$ $(x-5)^2<0$

But ${(x - 5)}^{2}$ $(x-5)^2$ is always $>0 AA x in RR$

So, there is no solution

graph{x^2-10x+25 [-10, 10, -5, 5]}

How do you solve x^2+25<10xx2+25<10xx^2+25<10x using a sign chart?