How do you solve #x^2+25<10x# using a sign chart?

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Answer 1 · 2016-12-14T07:33:31

The answer is #S={O/ }#

Let's rewrite the equation as

#x^2-10x+25<0#

Let's factorise,

#(x-5)^2<0#

But #(x-5)^2# is always #>0 AA x in RR#

So, there is no solution

graph{x^2-10x+25 [-10, 10, -5, 5]}