How do you solve $x^{2} - 2 y = 1$ $x^2 - 2y = 1$ & $x^{2} + 5 y = 29$ $x^2 + 5y = 29$ ?

Question

How do you solve $x^{2} - 2 y = 1$ $x^2 - 2y = 1$ & $x^{2} + 5 y = 29$ $x^2 + 5y = 29$ ?

1 Answer

Related questions

How do you solve systems of equations using the substitution method?
How do you check your solutions to a systems of equations using the substitution method?
When is the substitution method easier to use?
How do you know if a solution is "no solution" or "infinite" when using the substitution method?
How do you solve $y = - 6 x - 3$ $y=-6x-3$ and $y = 3$ $y=3$ using the substitution method?
How do you solve $12 y - 3 x = - 1$ $12y-3x=-1$ and $x - 4 y = 1$ $x-4y=1$ using the substitution method?
Which method do you use to solve the system of equations $y = \frac{1}{4} x - 14$ $y=1/4x-14$ and $y = \frac{19}{8} x + 7$ $y=19/8x+7$ ?
What are the 2 numbers if the sum is 70 and they differ by 11?
How do you solve $x + y = 5$ $x+y=5$ and $3 x + y = 15$ $3x+y=15$ using the substitution method?
What is the point of intersection of the lines $x + 2 y = 4$ $x+2y=4$ and $- x - 3 y = - 7$ $-x-3y=-7$ ?

Impact of this question

1994 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-19T16:00:26

x=pm3,y=4#

Explanation:

Multiplying the first equation by $- 1$ $-1$ and adding to the second we get
$7 y = 28$ $7y=28$
so
$y = 4$ $y=4$
plugging this in the first equation we get
$x = \pm 3$ $x=pm3$

Science

Math

Humanities

... and beyond

How do you solve $x^{2} - 2 y = 1$ $x^2 - 2y = 1$ & $x^{2} + 5 y = 29$ $x^2 + 5y = 29$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve x^2 - 2y = 1x2−2y=1x^2 - 2y = 1 & x^2 + 5y = 29x2+5y=29x^2 + 5y = 29?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $x^{2} - 2 y = 1$ $x^2 - 2y = 1$ & $x^{2} + 5 y = 29$ $x^2 + 5y = 29$ ?