How do you solve # (x-2) / 3=1 / x#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Konstantinos Michailidis Oct 2, 2015 Refer to exlpanation Explanation: We have that #(x-2)/3=1/x=>x(x-2)=3=>x^2-2x-3=0=>(x^2-2x+1)-4=0=>(x-1)^2-2^2=0=>[x-1-2]*[x-1+2]=0=>(x-3)*(x+1)=0=>x=3 or x=-1# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1136 views around the world You can reuse this answer Creative Commons License