Question

How do you solve `-x^2-4x>3`?

Answer 1

`-3 < x <-1`

Explanation:

`-x^2-4x>3=>` multiply by -1, reverse direction of inequality:
`x^2+4x<-3=>` solving by completing the square:
`x^2+4x+4<4-3`
`(x+2)^2<1`
`-1 < (x+2)<1`
`-3 < x <-1`
In interval form:
`(-3, -1)`