Question

How do you solve `x^2-4x>=5`?

Answer 1

`x^2−4x≥5`

`x^2−4x-5≥0`

`x^2+x-5x-5≥0`

`x(x+1)-5(x+1)≥0`

`(x-5)(x+1)≥0`

`:.(x-5)≥0` and `(x+1)≥0`

`x>=5` and `x>=-1`

`x<=5` as it will also be greater than -1 then.

-Sahar.