How do you solve x^2 – 6x -7 = 0? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Konstantinos Michailidis Mar 16, 2016 We can write this as follows x^2-6x-6-1=(x^2-1)-6(x+1)=(x-1)(x+1)-6(x+1)= (x+1)*(x-1-6)=(x+1)*(x-7) Now from x^2-6x-7=0=>(x+1)*(x-7)=0 we get that the roots are x=-1, x=7 Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph y=x^2-2x+3? How do you know if y=16-4x^2 opens up or down? How do you find the x-coordinate of the vertex for the graph 4x^2+16x+12=0? See all questions in Quadratic Functions and Their Graphs Impact of this question 935 views around the world You can reuse this answer Creative Commons License