How do you solve #x^2-6x=-8#? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Guillaume L. Mar 31, 2018 #x=4 or x=2# Explanation: [0]#x^2-6x=-8# [1]#x^2-6x+8=0# [2]#Delta=(-6)^2-4*1*8=4# [3]#x1=(-(-6)-sqrt(4))/2 or x2=(-(-6)+sqrt(4))/2# [4]#x1=2 and x2=4# \0/ here's our answer ! Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 1725 views around the world You can reuse this answer Creative Commons License