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How do you solve $x^{2} + 7 x + 10 > 0$ $x^2+7x+10>0$ using a sign chart?

1 Answer

Shwetank Mauria

Oct 1, 2016

$x < - 5$ $x<-5$ or $x ≻ 2$ $x>-2$

Explanation:

Just see https://socratic.org/questions/how-do-you-solve-x-3-7x-2-10x-0

and try on similar lines

we have

Sign Chart

$X X X X X X X X X X X - 5 X X X X X - 2$ $color(white)(XXXXXXXXXXX)-5color(white)(XXXXX)-2$

$(x + 5) X X X X - i v e X X X X + i v e X X + i v e$ $(x+5)color(white)(XXXX)-ive color(white)(XXXX)+ive color(white)(XX)+ive$

$(x + 2) X X X X - i v e X X X X - i v e X X + i v e$ $(x+2)color(white)(XXXX)-ive color(white)(XXXX)-ive color(white)(XX)+ive$

$(x + 5) (x + 2)$ $(x+5)(x+2)$
$X X X X X X X X + i v e X X X X - i v e X X + i v e$ $color(white)(XXXXXXXX)+ive color(white)(XXXX)-ive color(white)(XX)+ive$

$x^{2} + 7 x + 10 > 0$ $x^2+7x+10>0$ when $x < - 5$ $x<-5$ or $x > - 2$ $x > -2$

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