How do you solve #x^2+8=0#?

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Answer 1 · 2018-03-20T08:21:34

Given: #x^2+8=0#

Subtract #8# from both sides.

#x^2=0-8#

#=-8#

Take square root of both sides.

#x=sqrt(-8)#

#=sqrt(4*-2)#

#=sqrt(4)*sqrt(-2)#

#=2sqrt(-2)#

#=2sqrt(2)*sqrt(-1)#

#=2sqrt(2)i#

#=2isqrt(2)#