Question

How do you solve `x-2(x+10)=12`?

Answer 1

`x=-32`

Explanation:

Expand the brackets

`x-2(x + 10)=12 => x-2x-20=12`

`-x-20=12`

Add `x` to both sides

`-20=12+x`

Subtract 12 from both sides

#-32=x