Question

How do you solve `x^2 + x – 12 = 0`?

Answer 1

`x={3,-4}`

Explanation:

`x^2+x-12=0`
`(x+4)*(x-3)=0`

`if (x+4)=0" "then" "x=-4`
`if (x-3)=0" "then" "x=3`

`x={3,-4}`