How do you solve #(x-2)/(x+4)<=0# using a sign chart? Precalculus Solving Rational Inequalities Sign Charts 1 Answer VinÃcius Ferraz Jul 7, 2017 #x in (-4, 2] subset RR# Explanation: Parabola: #(x - 2)(x + 4) <= 0 and x ne -4# signs: #++ (-4)- - (2)+ + # #-4 < x <= 2# Answer link Related questions What is an inequality? What is a sign chart? How do I use a sign chart to solve #x^2>4#? How do I use a sign chart to solve #2x^2-7x<=-3#? How do I use a sign chart to solve #x^2<4#? How do I use a sign chart to solve #4x^2<=28x#? How do I use a sign chart to solve #2x^2-7x> -3#? How do I use a sign chart to solve #x^2+5x-9<0#? How do I use a sign chart to solve #2< -16t^2+6<5#? How do I use a sign chart to solve #x^2+1<0#? See all questions in Sign Charts Impact of this question 1650 views around the world You can reuse this answer Creative Commons License