x - 2y = -1 - - - eqn1x−2y=−1−−−eqn1
2x - y = 4 - - - eqn22x−y=4−−−eqn2
Using Substitution Method..
From eqn1eqn1
x - 2y = -1 - - - eqn1x−2y=−1−−−eqn1
Making xx the subject of formula;
x - 2y = -1x−2y=−1
x = -1 + 2yx=−1+2y
x = 2y - 1 - - - eqn3x=2y−1−−−eqn3
Substitute eqn3eqn3 into eqn2eqn2
2x - y = 4 - - - eqn22x−y=4−−−eqn2
2(2y - 1) - y = 42(2y−1)−y=4
4y - 2 - y = 44y−2−y=4
4y - y - 2 = 44y−y−2=4
3y - 2 = 43y−2=4
3y = 4 + 23y=4+2
3y = 63y=6
y = 6/3y=63
y = 2y=2
Substituting the value of yy into eqn3eqn3
x = 2y - 1 - - - eqn3x=2y−1−−−eqn3
x = 2(2) - 1x=2(2)−1
x = 4 - 1x=4−1
x = 3x=3
Therefore;
x = 3 and = 2x=3and=2
