Question

How do you solve `x+2y=12` and `x-2y=0`?

Answer 1

The solution for the system of equations is
`color(blue)(x=6,y=3`

Explanation:

`x+color(blue)(2y)=12` .....equation `(1)`
`x−color(blue)(2y)=0`....equation `(2)`

We can solve the equations through elimination
Adding the two equations results in elimination of `color(blue)(2y`

`x+cancelcolor(blue)(2y)=12`
`x−cancelcolor(blue)(2y)=0`

`2x=12`
`color(blue)(x=6`

Substituting `x` in equation `1` to find `y`
`x+2y=12`
`2y=12-6`
`2y=6`
`color(blue)(y=3`