How do you solve x-2y=-25 and 3x-y=0?

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Answer 1 · 2018-07-19T05:10:02

$x = 5$ $x=5$ and $y = 15$ $y=15$

As $3 x - y = 0$ $3x-y=0$ , we have $y = 3 x$ $y=3x$

hence $x - 2 y = - 25$ $x-2y=-25$ becomes

$x - 2 \cdot 3 x = - 25$ $x-2*3x=-25$

or $x - 6 x = - 25$ $x-6x=-25$

or $- 5 x = - 25$ $-5x=-25$

i.e. $x = \frac{- 25}{- 5} = \frac{25}{5} = 5$ $x=(-25)/(-5)=25/5=5$

and $y = 3 \cdot 5 = 15$ $y=3*5=15$