How do you solve $x- 2y = 6;3x - 6y = 18$ ?

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Answer 1 · 2017-01-11T12:10:32

Any pair $(x,y)$ for which $y=(x-6)/2$ will provide a solution for these equations (i.e. there is no single solution).

The two equations represent the same line; the second equation is simply the first multiplied by $3$

How do you solve x- 2y = 6;3x - 6y = 18x- 2y = 6;3x - 6y = 18?